log1p

(PHP 4 >= 4.1.0, PHP 5, PHP 7, PHP 8)

log1p — 返回 log(1 + number)，甚至当 number 的值接近零也能计算出准确结果

说明

log1p(float $number): float

log1p() 返回 log(1 + number)，甚至当 number 的值接近零也能计算出准确结果。 log() might only return log(1) in this case due to lack of precision.

参数

number: 要处理的参数

返回值

log(1 + number)

更新日志

版本	说明
5.3.0	此函数在所有平台上均可用

参见

expm1() - 返回 exp(number) - 1，甚至当 number 的值接近零也能计算出准确结果
log() - 自然对数
log10() - 以 10 为底的对数

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User Contributed Notes 1 note

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Anonymous ¶

19 years ago


Note that the benefit of this function for small argument values is lost if PHP is compiled against a C library that that not have builtin support for the log1p() function.

In this case, log1p() will be compiled by using log() instead, and the precision of the result will be identical to log(1), i.e. it will always be 0 for small numbers.
Sample log1p(1.0e-20):
- returns 0.0 if log1p() is approximated by using log()
- returns something very near from 1.0e-20, if log1p() is supported by the underlying C library.

One way to support log1p() correctly on any platform, so that the magnitude of the expected result is respected:

function log1p($x) {
return ($x>-1.0e-8 && $x<1.0e-8) ? ($x - $x*$x/2) : log(1+$x);
}

If you want better precision, you may use a better limited development, for small positive or negative values of x:

log(1+x) = x - x^2/2 + x^3/3 - ... + (-1)^(n-1)*x^n/n + ...

(This serial sum converges only for values of x in [0 ... 1] inclusive, and the ^ operator in the above formula means the exponentiation operator, not the PHP xor operation)

Note that log1p() is undefined for arguments lower than or equal to -1, and that the implied base of the log function is the Neperian "e" constant.

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官方地址：https://www.php.net/manual/en/function.log1p.php

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log1p

说明

参数

返回值

更新日志

参见

User Contributed Notes 1 note