<?php
$image = new Imagick("picture.jpg");
$width = $image->getImageWidth();
print "the image width is " . $width . " pixels";
?>
Will print:
the image width is 200 pixels
PHP - Manual: Imagick::getImageWidth
2024-12-22
(PECL imagick 2, PECL imagick 3)
Imagick::getImageWidth — Returns the image width
Returns the image width.
此函数没有参数。
Returns the image width.
错误时抛出 ImagickException。
<?php
$image = new Imagick("picture.jpg");
$width = $image->getImageWidth();
print "the image width is " . $width . " pixels";
?>
Will print:
the image width is 200 pixels
I am noticing that this is returning the original size of the image when it was opened, and not the size it may have been resized to with scaleImage or resizeImage.
"bob at majdak dot net" mentioned that this function does not return the resized image size.
I use this function in production code, and it correctly returns the width for an image resized with `resizeImage()`.
I have not tested it with `scaleImage()`.
官方地址:https://www.php.net/manual/en/imagick.getimagewidth.php