PHP - Manual: IntlDateFormatter::isLenient
2024-12-22
(PHP 5 >= 5.3.0, PHP 7, PHP 8, PECL intl >= 1.0.0)
IntlDateFormatter::isLenient -- datefmt_is_lenient — Get the lenient used for the IntlDateFormatter
面向对象风格
过程化风格
Check if the parser is strict or lenient in interpreting inputs that do not match the pattern exactly.
formatter
The formatter resource.
true
if parser is lenient, false
if parser is strict. By default the parser is lenient.
示例 #1 datefmt_is_lenient() example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'dd/mm/yyyy'
);
echo 'lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "\n Trying to do parse('35/13/1971').\nResult is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "\nError_msg is : " . intl_get_error_message();
echo "\nError_code is : " . intl_get_error_code();
}
datefmt_set_lenient($fmt,false);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
datefmt_parse($fmt, '35/13/1971');
echo "\n Trying to do parse('35/13/1971').Result is : " . datefmt_parse($fmt, '35/13/1971');
if (intl_get_error_code() != 0) {
echo "\nError_msg is : " . intl_get_error_message();
echo "\nError_code is : " . intl_get_error_code();
}
?>
示例 #2 OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,
IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
"dd/mm/yyyy"
);
echo "lenient of the formatter is : ";
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "\n Trying to do parse('35/13/1971').\nResult is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0){
echo "\nError_msg is : " . intl_get_error_message();
echo "\nError_code is : " . intl_get_error_code();
}
$fmt->setLenient(FALSE);
echo 'Now lenient of the formatter is : ';
if ($fmt->isLenient()) {
echo 'TRUE';
} else {
echo 'FALSE';
}
$fmt->parse('35/13/1971');
echo "\n Trying to do parse('35/13/1971').\nResult is : " . $fmt->parse('35/13/1971');
if (intl_get_error_code() != 0) {
echo "\nError_msg is : " . intl_get_error_message();
echo "\nError_code is : " . intl_get_error_code();
}
?>
以上例程会输出:
lenient of the formatter is : TRUE Trying to do parse('35/13/1971'). Result is : -2147483 Now lenient of the formatter is : FALSE Trying to do parse('35/13/1971'). Result is : Error_msg is : Date parsing failed: U_PARSE_ERROR Error_code is : 9
官方地址:https://www.php.net/manual/en/intldateformatter.islenient.php