mysqli_stmt::$affected_rows

mysqli_stmt_affected_rows

(PHP 5, PHP 7, PHP 8)

mysqli_stmt::$affected_rows -- mysqli_stmt_affected_rows — Returns the total number of rows changed, deleted, inserted, or matched by the last statement executed

说明

面向对象风格

int|string $mysqli_stmt->affected_rows;

过程化风格

mysqli_stmt_affected_rows(mysqli_stmt $statement): int|string

Returns the number of rows affected by INSERT, UPDATE, or DELETE query. Works like mysqli_stmt_num_rows() for SELECT statements.

参数

statement: 仅以过程化样式：由 mysqli_stmt_init() 返回的 mysqli_stmt 对象。

返回值

An integer greater than zero indicates the number of rows affected or retrieved. Zero indicates that no records were updated for an UPDATE statement, no rows matched the WHERE clause in the query or that no query has yet been executed. -1 indicates that the query returned an error or that, for a SELECT query, mysqli_stmt_affected_rows() was called prior to calling mysqli_stmt_store_result().

注意:
If the number of affected rows is greater than maximum PHP int value, the number of affected rows will be returned as a string value.

范例

示例 #1 mysqli_stmt_affected_rows() example

面向对象风格


<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* create temp table */
$mysqli->query("CREATE TEMPORARY TABLE myCountry LIKE Country");

$query = "INSERT INTO myCountry SELECT * FROM Country WHERE Code LIKE ?";

/* prepare statement */
$stmt = $mysqli->prepare($query);

/* Bind variable for placeholder */
$code = 'A%';
$stmt->bind_param("s", $code);

/* execute statement */
$stmt->execute();

printf("Rows inserted: %d\n", $stmt->affected_rows);

过程化风格


<?php

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* create temp table */
mysqli_query($link, "CREATE TEMPORARY TABLE myCountry LIKE Country");

$query = "INSERT INTO myCountry SELECT * FROM Country WHERE Code LIKE ?";

/* prepare statement */
$stmt = mysqli_prepare($link, $query);

/* Bind variable for placeholder */
$code = 'A%';
mysqli_stmt_bind_param($stmt, "s", $code);

/* execute statement */
mysqli_stmt_execute($stmt);

printf("Rows inserted: %d\n", mysqli_stmt_affected_rows($stmt));

以上例程会输出：

Rows inserted: 17

参见

mysqli_stmt_num_rows() - Returns the number of rows fetched from the server
mysqli_stmt_store_result() - Stores a result set in an internal buffer

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User Contributed Notes 2 notes

down

Carl Olsen ¶

16 years ago


It appears that an UPDATE prepared statement which contains the same data as that already in the database returns 0 for affected_rows.  I was expecting it to return 1, but it must be comparing the input values with the existing values and determining that no UPDATE has occurred.

down

-9

Chuck ¶

15 years ago


I'm not sure whether or not this is the intended behavior, but I noticed through testing that if you were to use transactions and prepared statements together and you added a single record to a database using a prepared statement, but later rolled it back, mysqli_stmt_affected_rows will still return 1.

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官方地址：https://www.php.net/manual/en/mysqli-stmt.affected-rows.php

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PHP官方手册 - 互联网笔记

mysqli_stmt::$affected_rows

mysqli_stmt_affected_rows

说明

参数

返回值

范例

参见

User Contributed Notes 2 notes